Base | Representation |
---|---|
bin | 11000001001011110011000… |
… | …00011010111100011010111 |
3 | 20222000111210221100000120020 |
4 | 30010233030003113203113 |
5 | 23430011102123143130 |
6 | 304534434142240223 |
7 | 14120333433351045 |
oct | 1404571403274327 |
9 | 228014727300506 |
10 | 53102104115415 |
11 | 15a13526449a23 |
12 | 5b57663286073 |
13 | 2382678961704 |
14 | d18226b9d395 |
15 | 6214931b9e10 |
hex | 304bcc0d78d7 |
53102104115415 has 16 divisors (see below), whose sum is σ = 84964608190176. Its totient is φ = 28320708326400.
The previous prime is 53102104115393. The next prime is 53102104115449. The reversal of 53102104115415 is 51451140120135.
53102104115415 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53102104115415 - 26 = 53102104115351 is a prime.
It is a super-2 number, since 2×531021041154152 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24804706 + ... + 26860335.
It is an arithmetic number, because the mean of its divisors is an integer number (5310288011886).
Almost surely, 253102104115415 is an apocalyptic number.
53102104115415 is a deficient number, since it is larger than the sum of its proper divisors (31862504074761).
53102104115415 is a wasteful number, since it uses less digits than its factorization.
53102104115415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51733570.
The product of its (nonzero) digits is 12000, while the sum is 33.
The spelling of 53102104115415 in words is "fifty-three trillion, one hundred two billion, one hundred four million, one hundred fifteen thousand, four hundred fifteen".
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