Base | Representation |
---|---|
bin | 100110101000110000101… |
… | …0101001110111100000111 |
3 | 200210122120211201122011011 |
4 | 1031101201111032330013 |
5 | 1144000303402042043 |
6 | 15143251123423051 |
7 | 1055436005536255 |
oct | 115214125167407 |
9 | 20718524648134 |
10 | 5310212534023 |
11 | 17680595a1821 |
12 | 7191a3524a87 |
13 | 2c699b9356c7 |
14 | 145030d735d5 |
15 | 931e677159d |
hex | 4d46154ef07 |
5310212534023 has 4 divisors (see below), whose sum is σ = 5362788895848. Its totient is φ = 5257636172200.
The previous prime is 5310212533993. The next prime is 5310212534051. The reversal of 5310212534023 is 3204352120135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5310212534023 - 25 = 5310212533991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5310212534083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26288180761 + ... + 26288180962.
It is an arithmetic number, because the mean of its divisors is an integer number (1340697223962).
Almost surely, 25310212534023 is an apocalyptic number.
5310212534023 is a deficient number, since it is larger than the sum of its proper divisors (52576361825).
5310212534023 is a wasteful number, since it uses less digits than its factorization.
5310212534023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52576361824.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 5310212534023 its reverse (3204352120135), we get a palindrome (8514564654158).
The spelling of 5310212534023 in words is "five trillion, three hundred ten billion, two hundred twelve million, five hundred thirty-four thousand, twenty-three".
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