Base | Representation |
---|---|
bin | 1111011101001000000… |
… | …10111001101001011001 |
3 | 1212202200121122200021021 |
4 | 13232210002321221121 |
5 | 32200023444414431 |
6 | 1043541524242441 |
7 | 53236332506614 |
oct | 7564402715131 |
9 | 1782617580237 |
10 | 531033201241 |
11 | 195234441954 |
12 | 86b01b40421 |
13 | 3b0cb5a614a |
14 | 1b9b897d17b |
15 | dc302eab11 |
hex | 7ba40b9a59 |
531033201241 has 2 divisors, whose sum is σ = 531033201242. Its totient is φ = 531033201240.
The previous prime is 531033201221. The next prime is 531033201253. The reversal of 531033201241 is 142102330135.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 516968190025 + 14065011216 = 719005^2 + 118596^2 .
It is a cyclic number.
It is not a de Polignac number, because 531033201241 - 27 = 531033201113 is a prime.
It is not a weakly prime, because it can be changed into another prime (531033201211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265516600620 + 265516600621.
It is an arithmetic number, because the mean of its divisors is an integer number (265516600621).
Almost surely, 2531033201241 is an apocalyptic number.
It is an amenable number.
531033201241 is a deficient number, since it is larger than the sum of its proper divisors (1).
531033201241 is an equidigital number, since it uses as much as digits as its factorization.
531033201241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 531033201241 its reverse (142102330135), we get a palindrome (673135531376).
The spelling of 531033201241 in words is "five hundred thirty-one billion, thirty-three million, two hundred one thousand, two hundred forty-one".
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