Base | Representation |
---|---|
bin | 110001011101001101… |
… | …001101111000000001 |
3 | 12002001212022212002122 |
4 | 301131031031320001 |
5 | 1332223424301340 |
6 | 40221221054025 |
7 | 3556644025100 |
oct | 613515157001 |
9 | 162055285078 |
10 | 53103353345 |
11 | 20580505389 |
12 | a360257315 |
13 | 50139a0193 |
14 | 27da95c037 |
15 | 15ac051db5 |
hex | c5d34de01 |
53103353345 has 24 divisors (see below), whose sum is σ = 74243810088. Its totient is φ = 36356812800.
The previous prime is 53103353341. The next prime is 53103353351. The reversal of 53103353345 is 54335330135.
It can be written as a sum of positive squares in 4 ways, for example, as 25107036304 + 27996317041 = 158452^2 + 167321^2 .
It is not a de Polignac number, because 53103353345 - 22 = 53103353341 is a prime.
It is a super-2 number, since 2×531033533452 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is not an unprimeable number, because it can be changed into a prime (53103353341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12026 + ... + 326115.
It is an arithmetic number, because the mean of its divisors is an integer number (3093492087).
Almost surely, 253103353345 is an apocalyptic number.
It is an amenable number.
53103353345 is a deficient number, since it is larger than the sum of its proper divisors (21140456743).
53103353345 is a wasteful number, since it uses less digits than its factorization.
53103353345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 338801 (or 338794 counting only the distinct ones).
The product of its (nonzero) digits is 121500, while the sum is 35.
The spelling of 53103353345 in words is "fifty-three billion, one hundred three million, three hundred fifty-three thousand, three hundred forty-five".
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