Base | Representation |
---|---|
bin | 1001111001001000… |
… | …00100011000110101 |
3 | 111201010200120101001 |
4 | 10330210010120311 |
5 | 41334112233123 |
6 | 2235002203301 |
7 | 245420140366 |
oct | 47444043065 |
9 | 14633616331 |
10 | 5311055413 |
11 | 2285a525a4 |
12 | 10427b3531 |
13 | 66842a751 |
14 | 385511b6d |
15 | 2113eb0ad |
hex | 13c904635 |
5311055413 has 4 divisors (see below), whose sum is σ = 5424056640. Its totient is φ = 5198054188.
The previous prime is 5311055381. The next prime is 5311055437. The reversal of 5311055413 is 3145501135.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5311055413 - 25 = 5311055381 is a prime.
It is a super-4 number, since 4×53110554134 (a number of 40 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5311055473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56500543 + ... + 56500636.
It is an arithmetic number, because the mean of its divisors is an integer number (1356014160).
Almost surely, 25311055413 is an apocalyptic number.
It is an amenable number.
5311055413 is a deficient number, since it is larger than the sum of its proper divisors (113001227).
5311055413 is a wasteful number, since it uses less digits than its factorization.
5311055413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113001226.
The product of its (nonzero) digits is 4500, while the sum is 28.
The square root of 5311055413 is about 72876.9882267373. The cubic root of 5311055413 is about 1744.7248398796.
Adding to 5311055413 its reverse (3145501135), we get a palindrome (8456556548).
The spelling of 5311055413 in words is "five billion, three hundred eleven million, fifty-five thousand, four hundred thirteen".
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