Base | Representation |
---|---|
bin | 111100011000011001011000… |
… | …0001001001011111001011111 |
3 | 2120122112102222012021000110112 |
4 | 1320300302300021023321133 |
5 | 1024103321403410141112 |
6 | 5121332304353200235 |
7 | 216605024205345233 |
oct | 17060626011137137 |
9 | 2518472865230415 |
10 | 531118611021407 |
11 | 14425a157762742 |
12 | 4b69a41826007b |
13 | 19a48368595ab6 |
14 | 95223c69125c3 |
15 | 4160931ec9a22 |
hex | 1e30cb024be5f |
531118611021407 has 8 divisors (see below), whose sum is σ = 543559432014720. Its totient is φ = 518681845727640.
The previous prime is 531118611021371. The next prime is 531118611021463. The reversal of 531118611021407 is 704120116811135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 531118611021407 - 214 = 531118611005023 is a prime.
It is a super-3 number, since 3×5311186110214073 (a number of 45 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531118611021487) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1013659907 + ... + 1014183732.
It is an arithmetic number, because the mean of its divisors is an integer number (67944929001840).
Almost surely, 2531118611021407 is an apocalyptic number.
531118611021407 is a deficient number, since it is larger than the sum of its proper divisors (12440820993313).
531118611021407 is a wasteful number, since it uses less digits than its factorization.
531118611021407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2027849773.
The product of its (nonzero) digits is 40320, while the sum is 41.
The spelling of 531118611021407 in words is "five hundred thirty-one trillion, one hundred eighteen billion, six hundred eleven million, twenty-one thousand, four hundred seven".
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