Base | Representation |
---|---|
bin | 111100011000011010111110… |
… | …1010011110010111101100111 |
3 | 2120122112202212002012100201001 |
4 | 1320300311331103302331213 |
5 | 1024103400431100212020 |
6 | 5121334034113414131 |
7 | 216605205412661413 |
oct | 17060657523627547 |
9 | 2518482762170631 |
10 | 531122053132135 |
11 | 144260663740453 |
12 | 4b69b018b6a347 |
13 | 19a487967440ca |
14 | 9522631b21d43 |
15 | 4160a8429e50a |
hex | 1e30d7d4f2f67 |
531122053132135 has 32 divisors (see below), whose sum is σ = 681269963673600. Its totient is φ = 396109816109568.
The previous prime is 531122053132031. The next prime is 531122053132141. The reversal of 531122053132135 is 531231350221135.
It is a cyclic number.
It is not a de Polignac number, because 531122053132135 - 29 = 531122053131623 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 531122053132094 and 531122053132103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66630357 + ... + 74174446.
It is an arithmetic number, because the mean of its divisors is an integer number (21289686364800).
Almost surely, 2531122053132135 is an apocalyptic number.
531122053132135 is a deficient number, since it is larger than the sum of its proper divisors (150147910541465).
531122053132135 is a wasteful number, since it uses less digits than its factorization.
531122053132135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140805247.
The product of its (nonzero) digits is 81000, while the sum is 37.
The spelling of 531122053132135 in words is "five hundred thirty-one trillion, one hundred twenty-two billion, fifty-three million, one hundred thirty-two thousand, one hundred thirty-five".
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