Base | Representation |
---|---|
bin | 110001011101111010… |
… | …000010010100100111 |
3 | 12002002200102202220122 |
4 | 301131322002110213 |
5 | 1332234431240003 |
6 | 40222320552155 |
7 | 3560145631151 |
oct | 613572022447 |
9 | 162080382818 |
10 | 53115102503 |
11 | 205870aa731 |
12 | a36418265b |
13 | 5016254c48 |
14 | 27dc339ad1 |
15 | 15ad0c3238 |
hex | c5de82527 |
53115102503 has 2 divisors, whose sum is σ = 53115102504. Its totient is φ = 53115102502.
The previous prime is 53115102473. The next prime is 53115102539. The reversal of 53115102503 is 30520151135.
It is a happy number.
53115102503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53115102503 - 28 = 53115102247 is a prime.
It is a super-2 number, since 2×531151025032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53115105503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26557551251 + 26557551252.
It is an arithmetic number, because the mean of its divisors is an integer number (26557551252).
Almost surely, 253115102503 is an apocalyptic number.
53115102503 is a deficient number, since it is larger than the sum of its proper divisors (1).
53115102503 is an equidigital number, since it uses as much as digits as its factorization.
53115102503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2250, while the sum is 26.
Adding to 53115102503 its reverse (30520151135), we get a palindrome (83635253638).
The spelling of 53115102503 in words is "fifty-three billion, one hundred fifteen million, one hundred two thousand, five hundred three".
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