53120035 has 4 divisors (see below), whose sum is σ = 63744048. Its totient is φ = 42496024.

The previous prime is 53120033. The next prime is 53120099. The reversal of 53120035 is 53002135.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53120035 - 2¹ = 53120033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53119994 and 53120021.

It is not an unprimeable number, because it can be changed into a prime (53120033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5311999 + ... + 5312008.

It is an arithmetic number, because the mean of its divisors is an integer number (15936012).

Almost surely, 2^53120035 is an apocalyptic number.

53120035 is a deficient number, since it is larger than the sum of its proper divisors (10624013).

53120035 is a wasteful number, since it uses less digits than its factorization.

53120035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10624012.

The product of its (nonzero) digits is 450, while the sum is 19.

The square root of 53120035 is about 7288.3492644082. The cubic root of 53120035 is about 375.9119375591.

The spelling of 53120035 in words is "fifty-three million, one hundred twenty thousand, thirty-five".