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53120443030 = 2553553118121
BaseRepresentation
bin110001011110001110…
…011010001010010110
312002010001111002201221
4301132032122022112
51332242313134110
640223031240554
73560242213204
oct613616321226
9162101432657
1053120443030
112058a118096
12a365b1915a
1350173a4a15
1427dcd2a074
1515ad7ca7da
hexc5e39a296

53120443030 has 32 divisors (see below), whose sum is σ = 97443878688. Its totient is φ = 20842348800.

The previous prime is 53120443007. The next prime is 53120443039. The reversal of 53120443030 is 3034402135.

53120443030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 53120442986 and 53120443004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53120443039) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2922370 + ... + 2940490.

It is an arithmetic number, because the mean of its divisors is an integer number (3045121209).

Almost surely, 253120443030 is an apocalyptic number.

53120443030 is a deficient number, since it is larger than the sum of its proper divisors (44323435658).

53120443030 is a wasteful number, since it uses less digits than its factorization.

53120443030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23712.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 53120443030 its reverse (3034402135), we get a palindrome (56154845165).

The spelling of 53120443030 in words is "fifty-three billion, one hundred twenty million, four hundred forty-three thousand, thirty".

Divisors: 1 2 5 10 53 106 265 530 5531 11062 18121 27655 36242 55310 90605 181210 293143 586286 960413 1465715 1920826 2931430 4802065 9604130 100227251 200454502 501136255 1002272510 5312044303 10624088606 26560221515 53120443030