Base | Representation |
---|---|
bin | 110001011110001110… |
… | …011010001010010110 |
3 | 12002010001111002201221 |
4 | 301132032122022112 |
5 | 1332242313134110 |
6 | 40223031240554 |
7 | 3560242213204 |
oct | 613616321226 |
9 | 162101432657 |
10 | 53120443030 |
11 | 2058a118096 |
12 | a365b1915a |
13 | 50173a4a15 |
14 | 27dcd2a074 |
15 | 15ad7ca7da |
hex | c5e39a296 |
53120443030 has 32 divisors (see below), whose sum is σ = 97443878688. Its totient is φ = 20842348800.
The previous prime is 53120443007. The next prime is 53120443039. The reversal of 53120443030 is 3034402135.
53120443030 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 53120442986 and 53120443004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53120443039) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2922370 + ... + 2940490.
It is an arithmetic number, because the mean of its divisors is an integer number (3045121209).
Almost surely, 253120443030 is an apocalyptic number.
53120443030 is a deficient number, since it is larger than the sum of its proper divisors (44323435658).
53120443030 is a wasteful number, since it uses less digits than its factorization.
53120443030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23712.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 53120443030 its reverse (3034402135), we get a palindrome (56154845165).
The spelling of 53120443030 in words is "fifty-three billion, one hundred twenty million, four hundred forty-three thousand, thirty".
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