53121113 has 4 divisors (see below), whose sum is σ = 53617680. Its totient is φ = 52624548.

The previous prime is 53121109. The next prime is 53121143. The reversal of 53121113 is 31112135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53121113 - 2² = 53121109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53121091 and 53121100.

It is not an unprimeable number, because it can be changed into a prime (53121143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248123 + ... + 248336.

It is an arithmetic number, because the mean of its divisors is an integer number (13404420).

Almost surely, 2^53121113 is an apocalyptic number.

It is an amenable number.

53121113 is a deficient number, since it is larger than the sum of its proper divisors (496567).

53121113 is a wasteful number, since it uses less digits than its factorization.

53121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496566.

The product of its digits is 90, while the sum is 17.

The square root of 53121113 is about 7288.4232176788. The cubic root of 53121113 is about 375.9144804184.

Adding to 53121113 its reverse (31112135), we get a palindrome (84233248).

The spelling of 53121113 in words is "fifty-three million, one hundred twenty-one thousand, one hundred thirteen".