Base | Representation |
---|---|
bin | 1111011101011101110… |
… | …01100110000111011101 |
3 | 1212210011022022211100012 |
4 | 13232232321212013131 |
5 | 32200412104430300 |
6 | 1044011551413005 |
7 | 53244003434036 |
oct | 7565671460735 |
9 | 1783138284305 |
10 | 531215311325 |
11 | 195318215956 |
12 | 86b52b24165 |
13 | 3b12a2385aa |
14 | 1b9d4c25a8d |
15 | dc412be435 |
hex | 7baee661dd |
531215311325 has 24 divisors (see below), whose sum is σ = 662449267200. Its totient is φ = 422560670400.
The previous prime is 531215311271. The next prime is 531215311339. The reversal of 531215311325 is 523113512135.
It is not a de Polignac number, because 531215311325 - 220 = 531214262749 is a prime.
It is a super-2 number, since 2×5312153113252 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 531215311291 and 531215311300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7761755 + ... + 7829895.
It is an arithmetic number, because the mean of its divisors is an integer number (27602052800).
Almost surely, 2531215311325 is an apocalyptic number.
It is an amenable number.
531215311325 is a deficient number, since it is larger than the sum of its proper divisors (131233955875).
531215311325 is a wasteful number, since it uses less digits than its factorization.
531215311325 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69917 (or 69912 counting only the distinct ones).
The product of its digits is 13500, while the sum is 32.
The spelling of 531215311325 in words is "five hundred thirty-one billion, two hundred fifteen million, three hundred eleven thousand, three hundred twenty-five".
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