Base | Representation |
---|---|
bin | 100110101001101011111… |
… | …1001001100000001011001 |
3 | 200210211201110122020202121 |
4 | 1031103113321030001121 |
5 | 1144013342111430440 |
6 | 15144220341501241 |
7 | 1055536211114554 |
oct | 115232771140131 |
9 | 20724643566677 |
10 | 5312201670745 |
11 | 176898a399672 |
12 | 719659711821 |
13 | 2c6c27a78298 |
14 | 14517d20169b |
15 | 932b11da34a |
hex | 4d4d7e4c059 |
5312201670745 has 4 divisors (see below), whose sum is σ = 6374642004900. Its totient is φ = 4249761336592.
The previous prime is 5312201670739. The next prime is 5312201670823. The reversal of 5312201670745 is 5470761022135.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1755341461449 + 3556860209296 = 1324893^2 + 1885964^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5312201670745 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531220167070 + ... + 531220167079.
It is an arithmetic number, because the mean of its divisors is an integer number (1593660501225).
Almost surely, 25312201670745 is an apocalyptic number.
It is an amenable number.
5312201670745 is a deficient number, since it is larger than the sum of its proper divisors (1062440334155).
5312201670745 is a wasteful number, since it uses less digits than its factorization.
5312201670745 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1062440334154.
The product of its (nonzero) digits is 352800, while the sum is 43.
The spelling of 5312201670745 in words is "five trillion, three hundred twelve billion, two hundred one million, six hundred seventy thousand, seven hundred forty-five".
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