Base | Representation |
---|---|
bin | 11111101010011… |
… | …100101000101011 |
3 | 1101000120211021011 |
4 | 133222130220223 |
5 | 2041443033120 |
6 | 124413524351 |
7 | 16110206242 |
oct | 3752345053 |
9 | 1330524234 |
10 | 531221035 |
11 | 252951254 |
12 | 129aa36b7 |
13 | 86096a97 |
14 | 507a1959 |
15 | 31983c5a |
hex | 1fa9ca2b |
531221035 has 4 divisors (see below), whose sum is σ = 637465248. Its totient is φ = 424976824.
The previous prime is 531221021. The next prime is 531221039. The reversal of 531221035 is 530122135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531221035 - 215 = 531188267 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 531220997 and 531221015.
It is not an unprimeable number, because it can be changed into a prime (531221039) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53122099 + ... + 53122108.
It is an arithmetic number, because the mean of its divisors is an integer number (159366312).
Almost surely, 2531221035 is an apocalyptic number.
531221035 is a deficient number, since it is larger than the sum of its proper divisors (106244213).
531221035 is a wasteful number, since it uses less digits than its factorization.
531221035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106244212.
The product of its (nonzero) digits is 900, while the sum is 22.
The square root of 531221035 is about 23048.2327955963. The cubic root of 531221035 is about 809.8882307804. Note that the first 3 decimals are identical.
The spelling of 531221035 in words is "five hundred thirty-one million, two hundred twenty-one thousand, thirty-five".
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