Base | Representation |
---|---|
bin | 1100101010100… |
… | …1010001011101 |
3 | 10200221212212201 |
4 | 3022221101131 |
5 | 102044402031 |
6 | 5134331501 |
7 | 1213350022 |
oct | 312512135 |
9 | 120855781 |
10 | 53122141 |
11 | 27a934a6 |
12 | 15959b91 |
13 | b00c527 |
14 | 70ab549 |
15 | 49e4d61 |
hex | 32a945d |
53122141 has 2 divisors, whose sum is σ = 53122142. Its totient is φ = 53122140.
The previous prime is 53122133. The next prime is 53122151. The reversal of 53122141 is 14122135.
53122141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42850116 + 10272025 = 6546^2 + 3205^2 .
It is a cyclic number.
It is not a de Polignac number, because 53122141 - 23 = 53122133 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53122151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26561070 + 26561071.
It is an arithmetic number, because the mean of its divisors is an integer number (26561071).
Almost surely, 253122141 is an apocalyptic number.
It is an amenable number.
53122141 is a deficient number, since it is larger than the sum of its proper divisors (1).
53122141 is an equidigital number, since it uses as much as digits as its factorization.
53122141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 240, while the sum is 19.
The square root of 53122141 is about 7288.4937401359. The cubic root of 53122141 is about 375.9169053023.
Adding to 53122141 its reverse (14122135), we get a palindrome (67244276).
The spelling of 53122141 in words is "fifty-three million, one hundred twenty-two thousand, one hundred forty-one".
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