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5312224147 = 29183180143
BaseRepresentation
bin1001111001010001…
…00001101110010011
3111201012212221120111
410330220201232103
541334412133042
62235043222151
7245433105646
oct47450415623
914635787514
105312224147
11228668069a
121043077957
136687496c9
14385737a5d
1521157c517
hex13ca21b93

5312224147 has 4 divisors (see below), whose sum is σ = 5495404320. Its totient is φ = 5129043976.

The previous prime is 5312224133. The next prime is 5312224153. The reversal of 5312224147 is 7414222135.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7414222135 = 51482844427.

It is a cyclic number.

It is not a de Polignac number, because 5312224147 - 27 = 5312224019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5312224157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91590043 + ... + 91590100.

It is an arithmetic number, because the mean of its divisors is an integer number (1373851080).

Almost surely, 25312224147 is an apocalyptic number.

5312224147 is a deficient number, since it is larger than the sum of its proper divisors (183180173).

5312224147 is a wasteful number, since it uses less digits than its factorization.

5312224147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183180172.

The product of its digits is 13440, while the sum is 31.

The square root of 5312224147 is about 72885.0063250323. The cubic root of 5312224147 is about 1744.8528100303.

The spelling of 5312224147 in words is "five billion, three hundred twelve million, two hundred twenty-four thousand, one hundred forty-seven".

Divisors: 1 29 183180143 5312224147