Base | Representation |
---|---|
bin | 100110101001110000000… |
… | …1001101001110000111101 |
3 | 200210212002010022111111022 |
4 | 1031103200021221300331 |
5 | 1144014133043021410 |
6 | 15144242211033525 |
7 | 1055542512460430 |
oct | 115234011516075 |
9 | 20725063274438 |
10 | 5312340204605 |
11 | 1768a5060a165 |
12 | 719697b9b8a5 |
13 | 2c6c4a691195 |
14 | 145193783817 |
15 | 932bd452455 |
hex | 4d4e0269c3d |
5312340204605 has 32 divisors (see below), whose sum is σ = 7298405991168. Its totient is φ = 3636295027200.
The previous prime is 5312340204599. The next prime is 5312340204637. The reversal of 5312340204605 is 5064020432135.
5312340204605 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5312340204605 - 26 = 5312340204541 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 96052010 + ... + 96107300.
It is an arithmetic number, because the mean of its divisors is an integer number (228075187224).
Almost surely, 25312340204605 is an apocalyptic number.
It is an amenable number.
5312340204605 is a deficient number, since it is larger than the sum of its proper divisors (1986065786563).
5312340204605 is a wasteful number, since it uses less digits than its factorization.
5312340204605 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60117.
The product of its (nonzero) digits is 86400, while the sum is 35.
The spelling of 5312340204605 in words is "five trillion, three hundred twelve billion, three hundred forty million, two hundred four thousand, six hundred five".
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