Base | Representation |
---|---|
bin | 110001011110011010… |
… | …110110001110010111 |
3 | 12002010021121202112121 |
4 | 301132122312032113 |
5 | 1332244132004303 |
6 | 40223225200411 |
7 | 3560312013430 |
oct | 613632661627 |
9 | 162107552477 |
10 | 53123703703 |
11 | 20590a44964 |
12 | a367030107 |
13 | 5017c76c05 |
14 | 27dd538487 |
15 | 15adc219bd |
hex | c5e6b6397 |
53123703703 has 4 divisors (see below), whose sum is σ = 60712804240. Its totient is φ = 45534603168.
The previous prime is 53123703671. The next prime is 53123703769. The reversal of 53123703703 is 30730732135.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30730732135 = 5 ⋅6146146427.
It is a cyclic number.
It is not a de Polignac number, because 53123703703 - 25 = 53123703671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53123703203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3794550258 + ... + 3794550271.
It is an arithmetic number, because the mean of its divisors is an integer number (15178201060).
Almost surely, 253123703703 is an apocalyptic number.
53123703703 is a deficient number, since it is larger than the sum of its proper divisors (7589100537).
53123703703 is an equidigital number, since it uses as much as digits as its factorization.
53123703703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7589100536.
The product of its (nonzero) digits is 39690, while the sum is 34.
The spelling of 53123703703 in words is "fifty-three billion, one hundred twenty-three million, seven hundred three thousand, seven hundred three".
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