Base | Representation |
---|---|
bin | 11000001010000111111100… |
… | …10101000001110010010111 |
3 | 20222002122102100012111012120 |
4 | 30011003332111001302113 |
5 | 23430342304121122020 |
6 | 304553004525351023 |
7 | 14122053466116012 |
oct | 1405037625016227 |
9 | 228078370174176 |
10 | 53124422442135 |
11 | 15a21a39577140 |
12 | 5b5ba51708473 |
13 | 23847c472a0b5 |
14 | d19342d24379 |
15 | 621d4c727740 |
hex | 3050fe541c97 |
53124422442135 has 16 divisors (see below), whose sum is σ = 92726264626560. Its totient is φ = 25757295729440.
The previous prime is 53124422442127. The next prime is 53124422442211.
53124422442135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53124422442135 - 23 = 53124422442127 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160983098145 + ... + 160983098474.
It is an arithmetic number, because the mean of its divisors is an integer number (5795391539160).
Almost surely, 253124422442135 is an apocalyptic number.
53124422442135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53124422442135 is a deficient number, since it is larger than the sum of its proper divisors (39601842184425).
53124422442135 is a wasteful number, since it uses less digits than its factorization.
53124422442135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 321966196638.
The product of its digits is 921600, while the sum is 42.
It can be divided in two parts, 5312442 and 2442135, that added together give a palindrome (7754577).
The spelling of 53124422442135 in words is "fifty-three trillion, one hundred twenty-four billion, four hundred twenty-two million, four hundred forty-two thousand, one hundred thirty-five".
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