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531245353143103 is a prime number
BaseRepresentation
bin111100011001010100011001…
…0100100000000101100111111
32120122222120010001220220012221
41320302220302210000230333
51024112410440401034403
65121510425052510211
7216620132042533144
oct17062506244005477
92518876101826187
10531245353143103
111442a8986347665
124b6baaa9a7b367
1319a572b6515791
1495285ab4483cb
154163d9dd0adbd
hex1e32a32900b3f

531245353143103 has 2 divisors, whose sum is σ = 531245353143104. Its totient is φ = 531245353143102.

The previous prime is 531245353143083. The next prime is 531245353143107. The reversal of 531245353143103 is 301341353542135.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 531245353143103 - 213 = 531245353134911 is a prime.

It is a super-2 number, since 2×5312453531431032 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 531245353143103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531245353143107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265622676571551 + 265622676571552.

It is an arithmetic number, because the mean of its divisors is an integer number (265622676571552).

Almost surely, 2531245353143103 is an apocalyptic number.

531245353143103 is a deficient number, since it is larger than the sum of its proper divisors (1).

531245353143103 is an equidigital number, since it uses as much as digits as its factorization.

531245353143103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 43.

The spelling of 531245353143103 in words is "five hundred thirty-one trillion, two hundred forty-five billion, three hundred fifty-three million, one hundred forty-three thousand, one hundred three".