Base | Representation |
---|---|
bin | 111100011001010110101101… |
… | …0001110011001101010111100 |
3 | 2120200000000220202202212111111 |
4 | 1320302231122032121222330 |
5 | 1024113001120231043030 |
6 | 5121513005211131404 |
7 | 216620366004261454 |
oct | 17062553216315274 |
9 | 2520000822685444 |
10 | 531250313534140 |
11 | 1442aaaa1360892 |
12 | 4b6bba53143b64 |
13 | 19a578c70b67c5 |
14 | 952891c158d64 |
15 | 416408e53b62a |
hex | 1e32b5a399abc |
531250313534140 has 48 divisors (see below), whose sum is σ = 1115950533465600. Its totient is φ = 212438252063232.
The previous prime is 531250313534123. The next prime is 531250313534159. The reversal of 531250313534140 is 41435313052135.
It is a junction number, because it is equal to n+sod(n) for n = 531250313534093 and 531250313534102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1157387962 + ... + 1157846878.
It is an arithmetic number, because the mean of its divisors is an integer number (23248969447200).
Almost surely, 2531250313534140 is an apocalyptic number.
It is an amenable number.
531250313534140 is an abundant number, since it is smaller than the sum of its proper divisors (584700219931460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531250313534140 is a wasteful number, since it uses less digits than its factorization.
531250313534140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 475654 (or 475652 counting only the distinct ones).
The product of its (nonzero) digits is 324000, while the sum is 40.
Adding to 531250313534140 its reverse (41435313052135), we get a palindrome (572685626586275).
The spelling of 531250313534140 in words is "five hundred thirty-one trillion, two hundred fifty billion, three hundred thirteen million, five hundred thirty-four thousand, one hundred forty".
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