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5312705342339 is a prime number
BaseRepresentation
bin100110101001111010111…
…1010100010101110000011
3200210220000120101102022002
41031103311322202232003
51144020410031423324
615144342333134215
71055554535213063
oct115236572425603
920726016342262
105312705342339
11176911873358a
1271977a32a36b
132c6ca8217605
141451ca0713a3
15932e052b3ae
hex4d4f5ea2b83

5312705342339 has 2 divisors, whose sum is σ = 5312705342340. Its totient is φ = 5312705342338.

The previous prime is 5312705342257. The next prime is 5312705342341. The reversal of 5312705342339 is 9332435072135.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5312705342339 - 224 = 5312688565123 is a prime.

Together with 5312705342341, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5312705342293 and 5312705342302.

It is not a weakly prime, because it can be changed into another prime (5312705342039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656352671169 + 2656352671170.

It is an arithmetic number, because the mean of its divisors is an integer number (2656352671170).

Almost surely, 25312705342339 is an apocalyptic number.

5312705342339 is a deficient number, since it is larger than the sum of its proper divisors (1).

5312705342339 is an equidigital number, since it uses as much as digits as its factorization.

5312705342339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2041200, while the sum is 47.

The spelling of 5312705342339 in words is "five trillion, three hundred twelve billion, seven hundred five million, three hundred forty-two thousand, three hundred thirty-nine".