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5313103331 is a prime number
BaseRepresentation
bin1001111001010111…
…11000010111100011
3111201021112121120212
410330223320113203
541340123301311
62235114124335
7245443430114
oct47453702743
914637477525
105313103331
112287121198
1210434206ab
13668996933
143858c620b
152116a2c8b
hex13caf85e3

5313103331 has 2 divisors, whose sum is σ = 5313103332. Its totient is φ = 5313103330.

The previous prime is 5313103309. The next prime is 5313103333. The reversal of 5313103331 is 1333013135.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5313103331 - 218 = 5312841187 is a prime.

It is a super-2 number, since 2×53131033312 = 56458134011766591122, which contains 22 as substring.

Together with 5313103333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5313103297 and 5313103306.

It is not a weakly prime, because it can be changed into another prime (5313103333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2656551665 + 2656551666.

It is an arithmetic number, because the mean of its divisors is an integer number (2656551666).

Almost surely, 25313103331 is an apocalyptic number.

5313103331 is a deficient number, since it is larger than the sum of its proper divisors (1).

5313103331 is an equidigital number, since it uses as much as digits as its factorization.

5313103331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1215, while the sum is 23.

The square root of 5313103331 is about 72891.0373845784. The cubic root of 5313103331 is about 1744.9490636276.

Adding to 5313103331 its reverse (1333013135), we get a palindrome (6646116466).

The spelling of 5313103331 in words is "five billion, three hundred thirteen million, one hundred three thousand, three hundred thirty-one".