Base | Representation |
---|---|
bin | 111100011001110010101010… |
… | …0110100100011100101001111 |
3 | 2120200012202212222112000211121 |
4 | 1320303211110310203211033 |
5 | 1024114442100204240210 |
6 | 5122000334544501411 |
7 | 216624622555323553 |
oct | 17063452464434517 |
9 | 2520182788460747 |
10 | 531310352415055 |
11 | 144323500784734 |
12 | 4b70b60a01a867 |
13 | 19a60474908045 |
14 | 952b7b5c4d863 |
15 | 41659053be6da |
hex | 1e33954d2394f |
531310352415055 has 8 divisors (see below), whose sum is σ = 637573033080144. Its totient is φ = 425047875144000.
The previous prime is 531310352415049. The next prime is 531310352415097. The reversal of 531310352415055 is 550514253013135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 531310352415055 - 27 = 531310352414927 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45041326 + ... + 55599835.
It is an arithmetic number, because the mean of its divisors is an integer number (79696629135018).
Almost surely, 2531310352415055 is an apocalyptic number.
531310352415055 is a deficient number, since it is larger than the sum of its proper divisors (106262680665089).
531310352415055 is a wasteful number, since it uses less digits than its factorization.
531310352415055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101697017.
The product of its (nonzero) digits is 675000, while the sum is 43.
The spelling of 531310352415055 in words is "five hundred thirty-one trillion, three hundred ten billion, three hundred fifty-two million, four hundred fifteen thousand, fifty-five".
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