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531314540133 = 31319697691651
BaseRepresentation
bin1111011101101001101…
…00000111111001100101
31212210102020001011200020
413232310310013321211
532201113010241013
61044025454305353
753246320034616
oct7566464077145
91783366034606
10531314540133
1119536922aa33
1286b801b8259
133b14496c070
141ba04095c0d
15dc49d70623
hex7bb4d07e65

531314540133 has 16 divisors (see below), whose sum is σ = 762953021376. Its totient is φ = 326945721600.

The previous prime is 531314540123. The next prime is 531314540201. The reversal of 531314540133 is 331045413135.

It is not a de Polignac number, because 531314540133 - 29 = 531314539621 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 531314540094 and 531314540103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (531314540123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 422358 + ... + 1114008.

It is an arithmetic number, because the mean of its divisors is an integer number (47684563836).

Almost surely, 2531314540133 is an apocalyptic number.

It is an amenable number.

531314540133 is a deficient number, since it is larger than the sum of its proper divisors (231638481243).

531314540133 is a wasteful number, since it uses less digits than its factorization.

531314540133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 711364.

The product of its (nonzero) digits is 32400, while the sum is 33.

Adding to 531314540133 its reverse (331045413135), we get a palindrome (862359953268).

The spelling of 531314540133 in words is "five hundred thirty-one billion, three hundred fourteen million, five hundred forty thousand, one hundred thirty-three".

Divisors: 1 3 13 39 19697 59091 256061 691651 768183 2074953 8991463 26974389 13623449747 40870349241 177104846711 531314540133