Base | Representation |
---|---|
bin | 1111011101101001101… |
… | …10010011100001110011 |
3 | 1212210102021010020012101 |
4 | 13232310312103201303 |
5 | 32201113132041201 |
6 | 1044025514441231 |
7 | 53246324636203 |
oct | 7566466234163 |
9 | 1783367106171 |
10 | 531315112051 |
11 | 195369590699 |
12 | 86b80433217 |
13 | 3b144b0c489 |
14 | 1ba041a4403 |
15 | dc49e34d01 |
hex | 7bb4d93873 |
531315112051 has 4 divisors (see below), whose sum is σ = 531387594504. Its totient is φ = 531242629600.
The previous prime is 531315112007. The next prime is 531315112063. The reversal of 531315112051 is 150211513135.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 531315112051 - 27 = 531315111923 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (531315112351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36230230 + ... + 36244891.
It is an arithmetic number, because the mean of its divisors is an integer number (132846898626).
Almost surely, 2531315112051 is an apocalyptic number.
531315112051 is a deficient number, since it is larger than the sum of its proper divisors (72482453).
531315112051 is an equidigital number, since it uses as much as digits as its factorization.
531315112051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72482452.
The product of its (nonzero) digits is 2250, while the sum is 28.
Adding to 531315112051 its reverse (150211513135), we get a palindrome (681526625186).
The spelling of 531315112051 in words is "five hundred thirty-one billion, three hundred fifteen million, one hundred twelve thousand, fifty-one".
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