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53133104013 = 3111610094061
BaseRepresentation
bin110001011110111110…
…101101001110001101
312002010221022100100020
4301132332231032031
51332304033312023
640224202452353
73560454634533
oct613676551615
9162127270306
1053133104013
1120596285510
12a36a2040b9
135019bb8822
1428008a4153
1515ae97bde3
hexc5efad38d

53133104013 has 8 divisors (see below), whose sum is σ = 77284514976. Its totient is φ = 32201881200.

The previous prime is 53133103997. The next prime is 53133104039. The reversal of 53133104013 is 31040133135.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53133104013 - 24 = 53133103997 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53133104083) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 805046998 + ... + 805047063.

It is an arithmetic number, because the mean of its divisors is an integer number (9660564372).

Almost surely, 253133104013 is an apocalyptic number.

It is an amenable number.

53133104013 is a deficient number, since it is larger than the sum of its proper divisors (24151410963).

53133104013 is a wasteful number, since it uses less digits than its factorization.

53133104013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1610094075.

The product of its (nonzero) digits is 1620, while the sum is 24.

Adding to 53133104013 its reverse (31040133135), we get a palindrome (84173237148).

The spelling of 53133104013 in words is "fifty-three billion, one hundred thirty-three million, one hundred four thousand, thirteen".

Divisors: 1 3 11 33 1610094061 4830282183 17711034671 53133104013