Base | Representation |
---|---|
bin | 1111011101101011100… |
… | …11011100110110100111 |
3 | 1212210110101021120211022 |
4 | 13232311303130312213 |
5 | 32201131233003111 |
6 | 1044031250201355 |
7 | 53246611116005 |
oct | 7566563346647 |
9 | 1783411246738 |
10 | 531331141031 |
11 | 195377639489 |
12 | 86b8588325b |
13 | 3b148232292 |
14 | 1ba06377a75 |
15 | dc4b54e2db |
hex | 7bb5cdcda7 |
531331141031 has 2 divisors, whose sum is σ = 531331141032. Its totient is φ = 531331141030.
The previous prime is 531331141021. The next prime is 531331141049. The reversal of 531331141031 is 130141133135.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 531331141031 - 222 = 531326946727 is a prime.
It is a super-2 number, since 2×5313311410312 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (531331141021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265665570515 + 265665570516.
It is an arithmetic number, because the mean of its divisors is an integer number (265665570516).
Almost surely, 2531331141031 is an apocalyptic number.
531331141031 is a deficient number, since it is larger than the sum of its proper divisors (1).
531331141031 is an equidigital number, since it uses as much as digits as its factorization.
531331141031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 531331141031 its reverse (130141133135), we get a palindrome (661472274166).
The spelling of 531331141031 in words is "five hundred thirty-one billion, three hundred thirty-one million, one hundred forty-one thousand, thirty-one".
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