5313410143135 has 4 divisors (see below), whose sum is σ = 6376092171768. Its totient is φ = 4250728114504.

The previous prime is 5313410143021. The next prime is 5313410143177.

5313410143135 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5313410143135 - 2¹⁵ = 5313410110367 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5313410143135.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531341014309 + ... + 531341014318.

It is an arithmetic number, because the mean of its divisors is an integer number (1594023042942).

Almost surely, 2^{5313410143135} is an apocalyptic number.

5313410143135 is a deficient number, since it is larger than the sum of its proper divisors (1062682028633).

5313410143135 is a wasteful number, since it uses less digits than its factorization.

5313410143135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1062682028632.

The product of its (nonzero) digits is 32400, while the sum is 34.

It can be divided in two parts, 5313410 and 143135, that added together give a palindrome (5456545).

The spelling of 5313410143135 in words is "five trillion, three hundred thirteen billion, four hundred ten million, one hundred forty-three thousand, one hundred thirty-five".