Base | Representation |
---|---|
bin | 11000001010011010001110… |
… | …00110010000110111111111 |
3 | 20222010120202001221211002120 |
4 | 30011031013012100313333 |
5 | 23431022402202240020 |
6 | 305001310233054023 |
7 | 14122551555420252 |
oct | 1405150706206777 |
9 | 228116661854076 |
10 | 53134233243135 |
11 | 15a26113506140 |
12 | 5b6192b257313 |
13 | 23856c91725a5 |
14 | d199d3cb7099 |
15 | 622223bb1740 |
hex | 305347190dff |
53134233243135 has 16 divisors (see below), whose sum is σ = 92743388933760. Its totient is φ = 25762052481440.
The previous prime is 53134233243103. The next prime is 53134233243139.
53134233243135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53134233243135 - 25 = 53134233243103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53134233243139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 161012827845 + ... + 161012828174.
It is an arithmetic number, because the mean of its divisors is an integer number (5796461808360).
Almost surely, 253134233243135 is an apocalyptic number.
53134233243135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53134233243135 is a deficient number, since it is larger than the sum of its proper divisors (39609155690625).
53134233243135 is a wasteful number, since it uses less digits than its factorization.
53134233243135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322025656038.
The product of its digits is 1166400, while the sum is 42.
It can be divided in two parts, 5313423 and 3243135, that added together give a palindrome (8556558).
The spelling of 53134233243135 in words is "fifty-three trillion, one hundred thirty-four billion, two hundred thirty-three million, two hundred forty-three thousand, one hundred thirty-five".
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