Base | Representation |
---|---|
bin | 100110101010010000100… |
… | …1000001100110111011111 |
3 | 200210221220002121021102102 |
4 | 1031110201020030313133 |
5 | 1144023401131440020 |
6 | 15144542312315315 |
7 | 1055611520502035 |
oct | 115244110146737 |
9 | 20727802537372 |
10 | 5313430343135 |
11 | 176945a9a93a2 |
12 | 7199410a2b3b |
13 | 2c709249b375 |
14 | 145258476555 |
15 | 93333edb475 |
hex | 4d52120cddf |
5313430343135 has 4 divisors (see below), whose sum is σ = 6376116411768. Its totient is φ = 4250744274504.
The previous prime is 5313430343113. The next prime is 5313430343197.
5313430343135 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5313430343135 - 242 = 915383832031 is a prime.
It is a super-2 number, since 2×53134303431352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531343034309 + ... + 531343034318.
It is an arithmetic number, because the mean of its divisors is an integer number (1594029102942).
Almost surely, 25313430343135 is an apocalyptic number.
5313430343135 is a deficient number, since it is larger than the sum of its proper divisors (1062686068633).
5313430343135 is a wasteful number, since it uses less digits than its factorization.
5313430343135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1062686068632.
The product of its (nonzero) digits is 291600, while the sum is 38.
It can be divided in two parts, 5313430 and 343135, that added together give a palindrome (5656565).
The spelling of 5313430343135 in words is "five trillion, three hundred thirteen billion, four hundred thirty million, three hundred forty-three thousand, one hundred thirty-five".
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