Base | Representation |
---|---|
bin | 110001011111000011… |
… | …100000010110100111 |
3 | 12002011000200021000012 |
4 | 301133003200112213 |
5 | 1332304344041043 |
6 | 40224245440435 |
7 | 3560501424311 |
oct | 613703402647 |
9 | 162130607005 |
10 | 53134362023 |
11 | 20596a64696 |
12 | a36a71011b |
13 | 501a239302 |
14 | 2800b107b1 |
15 | 15aeb29a18 |
hex | c5f0e05a7 |
53134362023 has 4 divisors (see below), whose sum is σ = 53136055848. Its totient is φ = 53132668200.
The previous prime is 53134361977. The next prime is 53134362041. The reversal of 53134362023 is 32026343135.
53134362023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32026343135 = 5 ⋅6405268627.
It is a cyclic number.
It is not a de Polignac number, because 53134362023 - 28 = 53134361767 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53134362623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 798953 + ... + 862898.
It is an arithmetic number, because the mean of its divisors is an integer number (13284013962).
Almost surely, 253134362023 is an apocalyptic number.
53134362023 is a deficient number, since it is larger than the sum of its proper divisors (1693825).
53134362023 is a wasteful number, since it uses less digits than its factorization.
53134362023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1693824.
The product of its (nonzero) digits is 38880, while the sum is 32.
The spelling of 53134362023 in words is "fifty-three billion, one hundred thirty-four million, three hundred sixty-two thousand, twenty-three".
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