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531400513949 is a prime number
BaseRepresentation
bin1111011101110011111…
…00000101100110011101
31212210122012211002120122
413232321330011212131
532201302012421244
61044042205124325
753251412561264
oct7567174054635
91783565732518
10531400513949
11195402811378
1286ba4b596a5
133b159711546
141ba116755db
15dc526a41ee
hex7bb9f0599d

531400513949 has 2 divisors, whose sum is σ = 531400513950. Its totient is φ = 531400513948.

The previous prime is 531400513939. The next prime is 531400513993. The reversal of 531400513949 is 949315004135.

It is an a-pointer prime, because the next prime (531400513993) can be obtained adding 531400513949 to its sum of digits (44).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 503830236100 + 27570277849 = 709810^2 + 166043^2 .

It is a cyclic number.

It is not a de Polignac number, because 531400513949 - 216 = 531400448413 is a prime.

It is a super-2 number, since 2×5314005139492 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (531400513909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265700256974 + 265700256975.

It is an arithmetic number, because the mean of its divisors is an integer number (265700256975).

Almost surely, 2531400513949 is an apocalyptic number.

It is an amenable number.

531400513949 is a deficient number, since it is larger than the sum of its proper divisors (1).

531400513949 is an equidigital number, since it uses as much as digits as its factorization.

531400513949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 44.

The spelling of 531400513949 in words is "five hundred thirty-one billion, four hundred million, five hundred thirteen thousand, nine hundred forty-nine".