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5314121 is a prime number
BaseRepresentation
bin10100010001011001001001
3100222222121022
4110101121021
52330022441
6305522225
763112031
oct24213111
910888538
105314121
112aaa63a
121943375
131140a67
149c48c1
156ee84b
hex511649

5314121 has 2 divisors, whose sum is σ = 5314122. Its totient is φ = 5314120.

The previous prime is 5314117. The next prime is 5314123. The reversal of 5314121 is 1214135.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4182025 + 1132096 = 2045^2 + 1064^2 .

It is a cyclic number.

It is not a de Polignac number, because 5314121 - 22 = 5314117 is a prime.

It is a Sophie Germain prime.

Together with 5314123, it forms a pair of twin primes.

It is a Chen prime.

It is an Ulam number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5314121.

It is not a weakly prime, because it can be changed into another prime (5314123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657060 + 2657061.

It is an arithmetic number, because the mean of its divisors is an integer number (2657061).

Almost surely, 25314121 is an apocalyptic number.

It is an amenable number.

5314121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5314121 is an equidigital number, since it uses as much as digits as its factorization.

5314121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 17.

The square root of 5314121 is about 2305.2377317752. The cubic root of 5314121 is about 174.5060465389.

Adding to 5314121 its reverse (1214135), we get a palindrome (6528256).

The spelling of 5314121 in words is "five million, three hundred fourteen thousand, one hundred twenty-one".