Base | Representation |
---|---|
bin | 100110101010101000110… |
… | …0010000010110101000111 |
3 | 200211000222200200021010111 |
4 | 1031111101202002311013 |
5 | 1144032032030033020 |
6 | 15145155042133451 |
7 | 1055640611203111 |
oct | 115252142026507 |
9 | 20730880607114 |
10 | 5314242424135 |
11 | 1769837340917 |
12 | 719b29051287 |
13 | 2c71917c1078 |
14 | 1452d42683b1 |
15 | 9338044cd5a |
hex | 4d551882d47 |
5314242424135 has 4 divisors (see below), whose sum is σ = 6377090908968. Its totient is φ = 4251393939304.
The previous prime is 5314242424133. The next prime is 5314242424187.
5314242424135 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5314242424135 - 21 = 5314242424133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5314242424133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531424242409 + ... + 531424242418.
It is an arithmetic number, because the mean of its divisors is an integer number (1594272727242).
Almost surely, 25314242424135 is an apocalyptic number.
5314242424135 is a deficient number, since it is larger than the sum of its proper divisors (1062848484833).
5314242424135 is a wasteful number, since it uses less digits than its factorization.
5314242424135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1062848484832.
The product of its digits is 460800, while the sum is 40.
The spelling of 5314242424135 in words is "five trillion, three hundred fourteen billion, two hundred forty-two million, four hundred twenty-four thousand, one hundred thirty-five".
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