Base | Representation |
---|---|
bin | 10100010001011011111111 |
3 | 100222222212001 |
4 | 110101123333 |
5 | 2330024203 |
6 | 305523131 |
7 | 63112411 |
oct | 24213377 |
9 | 10888761 |
10 | 5314303 |
11 | 2aaa795 |
12 | 19434a7 |
13 | 1140b77 |
14 | 9c49b1 |
15 | 6ee91d |
hex | 5116ff |
5314303 has 2 divisors, whose sum is σ = 5314304. Its totient is φ = 5314302.
The previous prime is 5314301. The next prime is 5314391. The reversal of 5314303 is 3034135.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5314303 - 21 = 5314301 is a prime.
Together with 5314301, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5314301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657151 + 2657152.
It is an arithmetic number, because the mean of its divisors is an integer number (2657152).
Almost surely, 25314303 is an apocalyptic number.
5314303 is a deficient number, since it is larger than the sum of its proper divisors (1).
5314303 is an equidigital number, since it uses as much as digits as its factorization.
5314303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 19.
The square root of 5314303 is about 2305.2772067584. The cubic root of 5314303 is about 174.5080386989.
Adding to 5314303 its reverse (3034135), we get a palindrome (8348438).
The spelling of 5314303 in words is "five million, three hundred fourteen thousand, three hundred three".
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