Base | Representation |
---|---|
bin | 1111011101110111111… |
… | …01011110111001000001 |
3 | 1212210201120122102022000 |
4 | 13232323331132321001 |
5 | 32201334203342423 |
6 | 1044045420134213 |
7 | 53252304105012 |
oct | 7567375367101 |
9 | 1783646572260 |
10 | 531434434113 |
11 | 19541a97a070 |
12 | 86bb4397369 |
13 | 3b16375994b |
14 | 1ba15d85009 |
15 | dc55654843 |
hex | 7bbbf5ee41 |
531434434113 has 64 divisors (see below), whose sum is σ = 869289926400. Its totient is φ = 318185556480.
The previous prime is 531434433991. The next prime is 531434434129. The reversal of 531434434113 is 311434434135.
531434434113 is a `hidden beast` number, since 531 + 4 + 3 + 4 + 4 + 3 + 4 + 113 = 666.
It is not a de Polignac number, because 531434434113 - 218 = 531434171969 is a prime.
It is a super-2 number, since 2×5314344341132 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (531434434133) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 32689495 + ... + 32705747.
It is an arithmetic number, because the mean of its divisors is an integer number (13582655100).
Almost surely, 2531434434113 is an apocalyptic number.
It is an amenable number.
531434434113 is a deficient number, since it is larger than the sum of its proper divisors (337855492287).
531434434113 is a wasteful number, since it uses less digits than its factorization.
531434434113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17599 (or 17593 counting only the distinct ones).
The product of its digits is 103680, while the sum is 36.
Adding to 531434434113 its reverse (311434434135), we get a palindrome (842868868248).
The spelling of 531434434113 in words is "five hundred thirty-one billion, four hundred thirty-four million, four hundred thirty-four thousand, one hundred thirteen".
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