Base | Representation |
---|---|
bin | 11000001010101101000010… |
… | …00111000101110110000111 |
3 | 20222011112210222002002222101 |
4 | 30011112201013011312013 |
5 | 23431204043314003020 |
6 | 305010100353212531 |
7 | 14123360060024665 |
oct | 1405264107056607 |
9 | 228145728062871 |
10 | 53144333344135 |
11 | 15a2a426780550 |
12 | 5b63889861147 |
13 | 238664880a507 |
14 | d1a2b1455c35 |
15 | 62261574400a |
hex | 3055a11c5d87 |
53144333344135 has 32 divisors (see below), whose sum is σ = 69804336536064. Its totient is φ = 38520696720000.
The previous prime is 53144333344087. The next prime is 53144333344139.
53144333344135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53144333344135 - 213 = 53144333335943 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53144333344139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 122717485 + ... + 123149785.
It is an arithmetic number, because the mean of its divisors is an integer number (2181385516752).
Almost surely, 253144333344135 is an apocalyptic number.
53144333344135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53144333344135 is a deficient number, since it is larger than the sum of its proper divisors (16660003191929).
53144333344135 is a wasteful number, since it uses less digits than its factorization.
53144333344135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 439815.
The product of its digits is 4665600, while the sum is 46.
It can be divided in two parts, 5314433 and 3344135, that added together give a palindrome (8658568).
The spelling of 53144333344135 in words is "fifty-three trillion, one hundred forty-four billion, three hundred thirty-three million, three hundred forty-four thousand, one hundred thirty-five".
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