Base | Representation |
---|---|
bin | 100110101010110100010… |
… | …1000111101100110000111 |
3 | 200211001222201011221012012 |
4 | 1031111220220331212013 |
5 | 1144033330302114141 |
6 | 15145301331444435 |
7 | 1055653326413234 |
oct | 115255050754607 |
9 | 20731881157165 |
10 | 5314630113671 |
11 | 1769a1616879a |
12 | 71a016a5671b |
13 | 2c7223c12268 |
14 | 14532d94678b |
15 | 933a44cdceb |
hex | 4d568a3d987 |
5314630113671 has 2 divisors, whose sum is σ = 5314630113672. Its totient is φ = 5314630113670.
The previous prime is 5314630113659. The next prime is 5314630113721. The reversal of 5314630113671 is 1763110364135.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5314630113671 - 218 = 5314629851527 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5314630113631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2657315056835 + 2657315056836.
It is an arithmetic number, because the mean of its divisors is an integer number (2657315056836).
Almost surely, 25314630113671 is an apocalyptic number.
5314630113671 is a deficient number, since it is larger than the sum of its proper divisors (1).
5314630113671 is an equidigital number, since it uses as much as digits as its factorization.
5314630113671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 5314630113671 in words is "five trillion, three hundred fourteen billion, six hundred thirty million, one hundred thirteen thousand, six hundred seventy-one".
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