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53147117689 is a prime number
BaseRepresentation
bin110001011111110100…
…001010100001111001
312002011220200022111021
4301133310022201321
51332321130231224
640225423102441
73561015021661
oct613764124171
9162156608437
1053147117689
11205a3187166
12a372a41a21
13501ca84243
1428026b11a1
1515b0ce91e4
hexc5fd0a879

53147117689 has 2 divisors, whose sum is σ = 53147117690. Its totient is φ = 53147117688.

The previous prime is 53147117687. The next prime is 53147117693. The reversal of 53147117689 is 98671174135.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35869329664 + 17277788025 = 189392^2 + 131445^2 .

It is a cyclic number.

It is not a de Polignac number, because 53147117689 - 21 = 53147117687 is a prime.

It is a super-2 number, since 2×531471176892 (a number of 22 digits) contains 22 as substring.

Together with 53147117687, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (53147117687) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26573558844 + 26573558845.

It is an arithmetic number, because the mean of its divisors is an integer number (26573558845).

Almost surely, 253147117689 is an apocalyptic number.

It is an amenable number.

53147117689 is a deficient number, since it is larger than the sum of its proper divisors (1).

53147117689 is an equidigital number, since it uses as much as digits as its factorization.

53147117689 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1270080, while the sum is 52.

The spelling of 53147117689 in words is "fifty-three billion, one hundred forty-seven million, one hundred seventeen thousand, six hundred eighty-nine".