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53150002301 = 114831818391
BaseRepresentation
bin110001011111111111…
…001010110001111101
312002012010002212102202
4301133333022301331
51332322400033201
640230005001245
73561051364634
oct613777126175
9162163085382
1053150002301
11205a4877440
12a3739b3225
135020554206
142802c2251b
1515b11b8c6b
hexc5ffcac7d

53150002301 has 4 divisors (see below), whose sum is σ = 57981820704. Its totient is φ = 48318183900.

The previous prime is 53150002289. The next prime is 53150002327. The reversal of 53150002301 is 10320005135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53150002301 - 234 = 35970133117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53150002601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2415909185 + ... + 2415909206.

It is an arithmetic number, because the mean of its divisors is an integer number (14495455176).

Almost surely, 253150002301 is an apocalyptic number.

It is an amenable number.

53150002301 is a deficient number, since it is larger than the sum of its proper divisors (4831818403).

53150002301 is a wasteful number, since it uses less digits than its factorization.

53150002301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4831818402.

The product of its (nonzero) digits is 450, while the sum is 20.

Adding to 53150002301 its reverse (10320005135), we get a palindrome (63470007436).

The spelling of 53150002301 in words is "fifty-three billion, one hundred fifty million, two thousand, three hundred one".

Divisors: 1 11 4831818391 53150002301