Base | Representation |
---|---|
bin | 1100101011000… |
… | …0000101011111 |
3 | 10201000022011021 |
4 | 3022300011133 |
5 | 102101300142 |
6 | 5135105011 |
7 | 1213524256 |
oct | 312600537 |
9 | 121008137 |
10 | 53150047 |
11 | 28002465 |
12 | 15972167 |
13 | b01c142 |
14 | 70b779d |
15 | 49ed267 |
hex | 32b015f |
53150047 has 2 divisors, whose sum is σ = 53150048. Its totient is φ = 53150046.
The previous prime is 53150039. The next prime is 53150051. The reversal of 53150047 is 74005135.
53150047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53150047 - 23 = 53150039 is a prime.
It is a super-2 number, since 2×531500472 = 5649854992204418, which contains 22 as substring.
It is equal to p3178501 and since 53150047 and 3178501 have the same sum of digits, it is a Honaker prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53150057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26575023 + 26575024.
It is an arithmetic number, because the mean of its divisors is an integer number (26575024).
Almost surely, 253150047 is an apocalyptic number.
53150047 is a deficient number, since it is larger than the sum of its proper divisors (1).
53150047 is an equidigital number, since it uses as much as digits as its factorization.
53150047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2100, while the sum is 25.
The square root of 53150047 is about 7290.4078761068. The cubic root of 53150047 is about 375.9827190451.
The spelling of 53150047 in words is "fifty-three million, one hundred fifty thousand, forty-seven".
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