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53150156113 = 497111069183
BaseRepresentation
bin110001011111111111…
…110000010101010001
312002012010101200102111
4301133333300111101
51332322414443423
640230012145321
73561052605235
oct613777602521
9162163350374
1053150156113
11205a4971a5a
12a373a68241
1350205a9222
142802c625c5
1515b11e960d
hexc5fff0551

53150156113 has 4 divisors (see below), whose sum is σ = 53151275008. Its totient is φ = 53149037220.

The previous prime is 53150156083. The next prime is 53150156123. The reversal of 53150156113 is 31165105135.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31165105135 = 56233021027.

It is a cyclic number.

It is not a de Polignac number, because 53150156113 - 29 = 53150155601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53150156123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 484881 + ... + 584302.

It is an arithmetic number, because the mean of its divisors is an integer number (13287818752).

Almost surely, 253150156113 is an apocalyptic number.

It is an amenable number.

53150156113 is a deficient number, since it is larger than the sum of its proper divisors (1118895).

53150156113 is a wasteful number, since it uses less digits than its factorization.

53150156113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1118894.

The product of its (nonzero) digits is 6750, while the sum is 31.

The spelling of 53150156113 in words is "fifty-three billion, one hundred fifty million, one hundred fifty-six thousand, one hundred thirteen".

Divisors: 1 49711 1069183 53150156113