Base | Representation |
---|---|
bin | 100110101011001001100… |
… | …1101111000011110111111 |
3 | 200211010211111022020000201 |
4 | 1031112103031320132333 |
5 | 1144041311133411020 |
6 | 15145500250104331 |
7 | 1056010122143140 |
oct | 115262315703677 |
9 | 20733744266021 |
10 | 5315344435135 |
11 | 176a2523aa009 |
12 | 71a19611b0a7 |
13 | 2c7308bc7197 |
14 | 14539a76bac7 |
15 | 933e707ea0a |
hex | 4d5933787bf |
5315344435135 has 8 divisors (see below), whose sum is σ = 7289615225376. Its totient is φ = 3644807612640.
The previous prime is 5315344435127. The next prime is 5315344435199.
5315344435135 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5315344435135 - 23 = 5315344435127 is a prime.
It is a super-3 number, since 3×53153444351353 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75933491896 + ... + 75933491965.
It is an arithmetic number, because the mean of its divisors is an integer number (911201903172).
Almost surely, 25315344435135 is an apocalyptic number.
5315344435135 is a deficient number, since it is larger than the sum of its proper divisors (1974270790241).
5315344435135 is a wasteful number, since it uses less digits than its factorization.
5315344435135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151866983873.
The product of its digits is 3240000, while the sum is 46.
The spelling of 5315344435135 in words is "five trillion, three hundred fifteen billion, three hundred forty-four million, four hundred thirty-five thousand, one hundred thirty-five".
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