Base | Representation |
---|---|
bin | 1100101011000… |
… | …1000011110101 |
3 | 10201000111122001 |
4 | 3022301003311 |
5 | 102101412122 |
6 | 5135135301 |
7 | 1213542016 |
oct | 312610365 |
9 | 121014561 |
10 | 53154037 |
11 | 28005462 |
12 | 15974531 |
13 | b020bc1 |
14 | 70b900d |
15 | 49ee527 |
hex | 32b10f5 |
53154037 has 2 divisors, whose sum is σ = 53154038. Its totient is φ = 53154036.
The previous prime is 53154029. The next prime is 53154043. The reversal of 53154037 is 73045135.
53154037 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52215076 + 938961 = 7226^2 + 969^2 .
It is a cyclic number.
It is not a de Polignac number, because 53154037 - 23 = 53154029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53153996 and 53154014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53154067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26577018 + 26577019.
It is an arithmetic number, because the mean of its divisors is an integer number (26577019).
Almost surely, 253154037 is an apocalyptic number.
It is an amenable number.
53154037 is a deficient number, since it is larger than the sum of its proper divisors (1).
53154037 is an equidigital number, since it uses as much as digits as its factorization.
53154037 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 28.
The square root of 53154037 is about 7290.6815182121. The cubic root of 53154037 is about 375.9921272118.
The spelling of 53154037 in words is "fifty-three million, one hundred fifty-four thousand, thirty-seven".
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