Base | Representation |
---|---|
bin | 110001100000010000… |
… | …000111001100100111 |
3 | 12002012102110112101202 |
4 | 301200100013030213 |
5 | 1332330014202241 |
6 | 40230244113115 |
7 | 3561134214461 |
oct | 614020071447 |
9 | 162172415352 |
10 | 53154444071 |
11 | 205a7330623 |
12 | a37539579b |
13 | 502144ab91 |
14 | 280365b131 |
15 | 15b1794d9b |
hex | c60407327 |
53154444071 has 2 divisors, whose sum is σ = 53154444072. Its totient is φ = 53154444070.
The previous prime is 53154444059. The next prime is 53154444073. The reversal of 53154444071 is 17044445135.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53154444071 is a prime.
Together with 53154444073, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53154444073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26577222035 + 26577222036.
It is an arithmetic number, because the mean of its divisors is an integer number (26577222036).
Almost surely, 253154444071 is an apocalyptic number.
53154444071 is a deficient number, since it is larger than the sum of its proper divisors (1).
53154444071 is an equidigital number, since it uses as much as digits as its factorization.
53154444071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 38.
The spelling of 53154444071 in words is "fifty-three billion, one hundred fifty-four million, four hundred forty-four thousand, seventy-one".
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