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53155002541 = 232311087067
BaseRepresentation
bin110001100000010010…
…001111100010101101
312002012110111220110211
4301200102033202231
51332330140040131
640230304102421
73561142031614
oct614022174255
9162173456424
1053155002541
11205a7682173
12a375604a11
1350215b5134
14280376487b
1515b18555b1
hexc6048f8ad

53155002541 has 4 divisors (see below), whose sum is σ = 55466089632. Its totient is φ = 50843915452.

The previous prime is 53155002443. The next prime is 53155002583. The reversal of 53155002541 is 14520055135.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 53155002541 - 219 = 53154478253 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53155092541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1155543511 + ... + 1155543556.

It is an arithmetic number, because the mean of its divisors is an integer number (13866522408).

Almost surely, 253155002541 is an apocalyptic number.

It is an amenable number.

53155002541 is a deficient number, since it is larger than the sum of its proper divisors (2311087091).

53155002541 is a wasteful number, since it uses less digits than its factorization.

53155002541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2311087090.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 53155002541 its reverse (14520055135), we get a palindrome (67675057676).

The spelling of 53155002541 in words is "fifty-three billion, one hundred fifty-five million, two thousand, five hundred forty-one".

Divisors: 1 23 2311087067 53155002541