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53201201003 = 475271119389
BaseRepresentation
bin110001100011000010…
…011110011101101011
312002022200110000211222
4301203002132131223
51332424001413003
640235034212255
73562242514166
oct614302363553
9162280400758
1053201201003
1120620766815
12a388b8408b
13502b03c0c2
14280994cadd
1515b592dc38
hexc6309e76b

53201201003 has 4 divisors (see below), whose sum is σ = 53202367920. Its totient is φ = 53200034088.

The previous prime is 53201200991. The next prime is 53201201023. The reversal of 53201201003 is 30010210235.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30010210235 = 56002042047.

It is a cyclic number.

It is not a de Polignac number, because 53201201003 - 230 = 52127459179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (53201201023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 512168 + ... + 607221.

It is an arithmetic number, because the mean of its divisors is an integer number (13300591980).

Almost surely, 253201201003 is an apocalyptic number.

53201201003 is a deficient number, since it is larger than the sum of its proper divisors (1166917).

53201201003 is a wasteful number, since it uses less digits than its factorization.

53201201003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1166916.

The product of its (nonzero) digits is 180, while the sum is 17.

Adding to 53201201003 its reverse (30010210235), we get a palindrome (83211411238).

The spelling of 53201201003 in words is "fifty-three billion, two hundred one million, two hundred one thousand, three".

Divisors: 1 47527 1119389 53201201003