Base | Representation |
---|---|
bin | 1111011110111100111… |
… | …01110001100010001111 |
3 | 1212212012220221002112011 |
4 | 13233132131301202033 |
5 | 32204030402340211 |
6 | 1044223055522051 |
7 | 53302533433621 |
oct | 7573635614217 |
9 | 1785186832464 |
10 | 532013324431 |
11 | 195697719a16 |
12 | 87136229327 |
13 | 3b226673cb4 |
14 | 1ba6cbd4c11 |
15 | dc8b3a2921 |
hex | 7bde77188f |
532013324431 has 2 divisors, whose sum is σ = 532013324432. Its totient is φ = 532013324430.
The previous prime is 532013324419. The next prime is 532013324473. The reversal of 532013324431 is 134423310235.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 532013324431 - 231 = 529865840783 is a prime.
It is a super-2 number, since 2×5320133244312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 532013324393 and 532013324402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (532013324411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 266006662215 + 266006662216.
It is an arithmetic number, because the mean of its divisors is an integer number (266006662216).
Almost surely, 2532013324431 is an apocalyptic number.
532013324431 is a deficient number, since it is larger than the sum of its proper divisors (1).
532013324431 is an equidigital number, since it uses as much as digits as its factorization.
532013324431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 532013324431 its reverse (134423310235), we get a palindrome (666436634666).
The spelling of 532013324431 in words is "five hundred thirty-two billion, thirteen million, three hundred twenty-four thousand, four hundred thirty-one".
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