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532015324340 = 225122827216571
BaseRepresentation
bin1111011110111101001…
…01011001110010110100
31212212020001200200212212
413233132211121302310
532204031410334330
61044223210432552
753302556433353
oct7573645316264
91785201620785
10532015324340
11195698865535
1287136a32758
133b226bc4386
141ba6d19599a
15dc8b64a295
hex7bde959cb4

532015324340 has 24 divisors (see below), whose sum is σ = 1117246435872. Its totient is φ = 212803414560.

The previous prime is 532015324339. The next prime is 532015324349. The reversal of 532015324340 is 43423510235.

It is a junction number, because it is equal to n+sod(n) for n = 532015324297 and 532015324306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (532015324349) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2348255 + ... + 2564825.

It is an arithmetic number, because the mean of its divisors is an integer number (46551934828).

Almost surely, 2532015324340 is an apocalyptic number.

It is an amenable number.

532015324340 is an abundant number, since it is smaller than the sum of its proper divisors (585231111532).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

532015324340 is a wasteful number, since it uses less digits than its factorization.

532015324340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339407 (or 339405 counting only the distinct ones).

The product of its (nonzero) digits is 43200, while the sum is 32.

Adding to 532015324340 its reverse (43423510235), we get a palindrome (575438834575).

The spelling of 532015324340 in words is "five hundred thirty-two billion, fifteen million, three hundred twenty-four thousand, three hundred forty".

Divisors: 1 2 4 5 10 20 122827 216571 245654 433142 491308 614135 866284 1082855 1228270 2165710 2456540 4331420 26600766217 53201532434 106403064868 133003831085 266007662170 532015324340